On 7/24/14, Andrea Giammarchi <andrea.giammar...@gmail.com> wrote: > What is this about? Not an answer nor a solution to what I've said... > Just think that NaN is rarely an explicit value, rather something > potentially generated at runtime. Would > you .some(Number.isNAN.bind(Number)) all the Arrays? I don't think so, > at least I wouldn't >
It looked like you were trying to determine if a finite number is in an array. Is that right? That answer to how to do that would be: Number.isFinite(v) && arr.indexOf(v) != -1; -- Garrett @xkit ChordCycles.com garretts.github.io _______________________________________________ es-discuss mailing list es-discuss@mozilla.org https://mail.mozilla.org/listinfo/es-discuss
