On 9/18/14, 12:51 PM, Andreas Rossberg wrote:
Well, nothing has to go there. Since B does not have an extends
clause, it has -- according to Allen's gist -- its `this` initialized
implicitly (with an object having the derived constructor's prototype,
like you want).
Wait. How does the |new super()| invocation know what prototype to use,
exactly? Is it basically passing in the new^ value as some sort of
hidden state under the hood without exposing it with a name?
What new^ adds to the table is the ability to bypass this mechanism
and implement non-standard inheritance or creation patterns within the
class syntax.
Well, it adds the ability to explain what happens when you do:
class A extends HTMLElement {
...
}
right?
-Boris
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