Allen Wirfs-Brock wrote:
Well, they do for normal loop completions (according to the spec.) but not for
breaks. I this the latter is a bug. In particular, I think it is pretty
obvious that:
eval(“ {0; while (true) {1; break}; 2}”)
(single quotes might avoid the smart-dumb transformation that happened
here, which frustrated copy-paste into JS console :-|.)
should evaluate to 1
Why? Completion is on the 2; expression statement at the end. The break
doesn't break from the block.
It is a little less obvious for:
eval(“{0; L: while (true) {1; while (true) {2; break L; 3}; 4}; 5}”)
but, I think that consistency with the first case requires this to evaluate to
2.
The 3; and 4; statements are not reached, but 5; is -- again something
seems wrong with these examples.
/be
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