Unless the theoretical model omits I^2R losses, you cannot achieve the same
efficiency on flat v hilly. I think others have said as much, too. Peri
-----Original message-----
From: damon henry <[email protected]>
To: EV List <[email protected]>
Sent: Fri, Nov 22, 2013 17:11:29 GMT+00:00
Subject: Re: [EVDL] EVLN: Kia Soul EV goes global
andaimsfor120-miledrivingrange
Peri,
It is obvious to anyone that has attempted anything like this in the real
world with real parts that a vehicle will be more efficient on level ground
than with hills. It is only in a theoretical world and using math that you
can create and drive a hilly route and do it as efficiently as a flat level
route. There are inefficiencies in the real world that will present a
greater loss going up hill than you will get back going down hill.
damon
From: [email protected]
To: [email protected]
Date: Fri, 22 Nov 2013 06:38:35 -0800
Subject: Re: [EVDL] EVLN: Kia Soul EV goes global
andaimsfor120-miledrivingrange
You are right that constant speed eliminates the effects of air drag (an
other mechanical restance effects). But then the question goes back to
drive train efficiencies.
How are you going to maintain constant speed? In an ideal course, I
suppose
your downhills could be designed so that the force of gravity exactly
matches the resistive forces (i.e. wind resistance). Thus zero power and
zero regen.
But even then, going uphill, you will need to use more power than you
would
on the level. How is that going to be equally efficient?
Peri
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