On Thu, Feb 21, 2013 at 10:56 PM, meekerdb <meeke...@verizon.net> wrote:
> On 2/21/2013 7:10 PM, Joseph Knight wrote: > > Question: Why is the "derivation"* of the Born Rule in (Everett, 1957) not > considered satisfactory**? > > *Everett shows that the amplitude-squared rule for subjective > probability is the only measure consistent with an agreeable additivity > condition. > > > Gleason's theorem is to the same effect. But both start with the > assumption that the wave-function amplitude determines the probability - > and then they show it must be via the Born rule. > OK, I see, thanks. I suppose then that the decision-theory derivation drops this assumption? > Brent > > > **It is apparently not satisfactory because there have been multiple > later attempts to derive the Born Rule from certain other (e.g., > decision-theoretic) assumptions in an Everett framework (Deutsch, Wallace). > I have not yet studied these later works so cannot yet comment on them (but > would appreciate any remarks/opinions that Everything-listers have to > offer). > > -- > Joseph Knight -- > You received this message because you are subscribed to the Google Groups > "Everything List" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to everything-list+unsubscr...@googlegroups.com. > To post to this group, send email to everything-list@googlegroups.com. > Visit this group at http://groups.google.com/group/everything-list?hl=en. > For more options, visit https://groups.google.com/groups/opt_out. > > > > No virus found in this message. > Checked by AVG - www.avg.com > Version: 2013.0.2899 / Virus Database: 2639/6117 - Release Date: 02/19/13 > > > -- > You received this message because you are subscribed to the Google Groups > "Everything List" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to everything-list+unsubscr...@googlegroups.com. > To post to this group, send email to everything-list@googlegroups.com. > Visit this group at http://groups.google.com/group/everything-list?hl=en. > For more options, visit https://groups.google.com/groups/opt_out. > > > -- Joseph Knight -- You received this message because you are subscribed to the Google Groups "Everything List" group. To unsubscribe from this group and stop receiving emails from it, send an email to everything-list+unsubscr...@googlegroups.com. To post to this group, send email to everything-list@googlegroups.com. Visit this group at http://groups.google.com/group/everything-list?hl=en. For more options, visit https://groups.google.com/groups/opt_out.
