On Friday, April 20, 2018 at 4:21:15 AM UTC, agrays...@gmail.com wrote: > > > > On Friday, April 20, 2018 at 2:54:37 AM UTC, Brent wrote: >> >> >> >> On 4/19/2018 7:28 PM, agrays...@gmail.com wrote: >> >> >> >> On Friday, April 20, 2018 at 2:13:20 AM UTC, Brent wrote: >>> >>> >>> >>> On 4/19/2018 6:39 PM, agrays...@gmail.com wrote: >>> >>> >>> >>> On Friday, April 20, 2018 at 12:44:04 AM UTC, Brent wrote: >>>> >>>> >>>> >>>> On 4/19/2018 5:29 PM, smitra wrote: >>>> > One can a priori rule out any non-local effects using the fact that >>>> > the dynamics as described by the Schrödinger equation is local. So, >>>> in >>>> > any theory where there is no collapse and everything follows from >>>> only >>>> > the Schrödinger equation, there cannot be non-local effects >>>> >>>> The wave-function exists in configuration space so a point in it >>>> already >>>> refers to multiple points in 3space. >>>> >>>> Brent >>>> >>> >>> I've met WF's with variables of space and time. They don't have multiple >>> points in 3 space. Please elaborate as to your meaning. AG >>> >>> >>> The wave function for two particles is a function of six spacial >>> coordinates. >>> >>> Brent >>> >> >> OK, simple, but how is this responsive to smitra's comment? AG >> >> >> So a measurement on one can, assuming some conserved quantity entangling >> them, will have an effect on the other, even if the all the details of >> measurement and decoherence are included and the measurement is treated as >> Everett does. It still zeroes out cross terms in the density matrix that >> correspond ot violation of the conservation law and that entails changing >> the wave function at remote places. >> >> Brent >> > > *Generally speaking, IIUC, any two systems which interact will become > entangled. Does this in principle imply that the property of non locality > exists between them, such as demonstrated by the singlet state, or are > additional assumptions or conditions needed? AG * >
*Does entanglement -- which occurs whenever two systems interact -- imply non-locality? AG* -- You received this message because you are subscribed to the Google Groups "Everything List" group. To unsubscribe from this group and stop receiving emails from it, send an email to everything-list+unsubscr...@googlegroups.com. To post to this group, send email to everything-list@googlegroups.com. Visit this group at https://groups.google.com/group/everything-list. For more options, visit https://groups.google.com/d/optout.
