> On 20 Apr 2018, at 13:18, agrayson2...@gmail.com wrote: > > > > On Friday, April 20, 2018 at 4:21:15 AM UTC, agrays...@gmail.com wrote: > > > On Friday, April 20, 2018 at 2:54:37 AM UTC, Brent wrote: > > > On 4/19/2018 7:28 PM, agrays...@gmail.com <> wrote: >> >> >> On Friday, April 20, 2018 at 2:13:20 AM UTC, Brent wrote: >> >> >> On 4/19/2018 6:39 PM, agrays...@gmail.com <> wrote: >>> >>> >>> On Friday, April 20, 2018 at 12:44:04 AM UTC, Brent wrote: >>> >>> >>> On 4/19/2018 5:29 PM, smitra wrote: >>> > One can a priori rule out any non-local effects using the fact that >>> > the dynamics as described by the Schrödinger equation is local. So, in >>> > any theory where there is no collapse and everything follows from only >>> > the Schrödinger equation, there cannot be non-local effects >>> >>> The wave-function exists in configuration space so a point in it already >>> refers to multiple points in 3space. >>> >>> Brent >>> >>> I've met WF's with variables of space and time. They don't have multiple >>> points in 3 space. Please elaborate as to your meaning. AG >> >> The wave function for two particles is a function of six spacial coordinates. >> >> Brent >> >> OK, simple, but how is this responsive to smitra's comment? AG > > So a measurement on one can, assuming some conserved quantity entangling > them, will have an effect on the other, even if the all the details of > measurement and decoherence are included and the measurement is treated as > Everett does. It still zeroes out cross terms in the density matrix that > correspond ot violation of the conservation law and that entails changing the > wave function at remote places. > > Brent > > Generally speaking, IIUC, any two systems which interact will become > entangled. Does this in principle imply that the property of non locality > exists between them, such as demonstrated by the singlet state, or are > additional assumptions or conditions needed? AG > > Does entanglement -- which occurs whenever two systems interact -- imply > non-locality? AG
Let me try to explain. With both QM (“well understood”, without collapse) and Mechanism, (without waves except those that consciousness filters from the many “histories” in arithmetic, it seems that the “winner idea” is that you are multiplied by the unknown. So you are in all histories/computations that you cannot distinguish. For example, if you send a photon, and if your first person mind is independent of which path the photon would take (when in a superposition of taking tow different path), you are in both histories, and will fuse if you don’t get interested in which path the photon has gone. But Everett used mechanism, which rises the problem of justifying the universal wave from the completion of all universal numbers below our substitution level, as our first person is independent, isolated to those "fine grained” details. But the multiplication is due only to intrinsic ignorance by “isolation”. Being space separated is a form of isolation, that is a situation when your state of mind is totally independent of what happens there , and the multiplication (I reason in mechanism) “develops”. So entailment does not imply non locality, only the impossibility to share the universe/histories/computation with someone you are totally isolated from. Each of such strongly isolated Alice and Bob will met only there own Bob and Alice, if them decide to compare the result. The apparent action at a distance is only due to ignorance of which computations we are in, and with whom we share them most probably. Bruno > > -- > You received this message because you are subscribed to the Google Groups > "Everything List" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to everything-list+unsubscr...@googlegroups.com > <mailto:everything-list+unsubscr...@googlegroups.com>. > To post to this group, send email to everything-list@googlegroups.com > <mailto:everything-list@googlegroups.com>. > Visit this group at https://groups.google.com/group/everything-list > <https://groups.google.com/group/everything-list>. > For more options, visit https://groups.google.com/d/optout > <https://groups.google.com/d/optout>. -- You received this message because you are subscribed to the Google Groups "Everything List" group. To unsubscribe from this group and stop receiving emails from it, send an email to everything-list+unsubscr...@googlegroups.com. To post to this group, send email to everything-list@googlegroups.com. Visit this group at https://groups.google.com/group/everything-list. For more options, visit https://groups.google.com/d/optout.
