On 5/9/06, Axel Liljencrantz <[EMAIL PROTECTED]> wrote:
On 5/9/06, Philip Ganchev <[EMAIL PROTECTED]> wrote:
> On 5/9/06, Axel Liljencrantz <[EMAIL PROTECTED]> wrote:
>
> > set foo[(seq 3 5)] foo bar baz
> >
> > [...] Parameter expansion will make sure that the
> > former example gets expanded into
> >
> > set foo[3] foo[4] foo[5] foo bar baz
>
> Is it not possible to instead make parameter expansion convert it to
> "set foo[3 4 5] foo bar baz"? This is the more intuitive behavior to
> me. The other one seems a bit magical and surprising.
>
How would you note the difference? In either case, you write 'set
foo[(seq 3 5)] foo bar baz' and you get the same results.
The kludge is apparent in that, as you mentioned,
set foo[1 (seq 4 6)] a b c d
refers to the indexes 1 4 1 5 1 6, rather than 1 4 5 6 as one would
expect. It's surprising; I would much prefer the latter. Instead of
creating an illusion, why not change make expansion more intuitive?
But this
way, we don't make parameter expansion behave in a different, magical
way when operating on the set builtin, instead the same rules as
always apply.
Sorry, I was not clear. I did not mean anything about the "set"
builtin. I was suggesting that
foo[(seq 1 2)]
should expand to
foo[1 2]
not to
foo[1] foo[2]
One way to achieve this is to make expansion work differently with
brackets than with other strings. Currently,
foo(seq 1 2)
Expands to
foo1 foo2
Another way is to make the above behave instead as a concatenation of
the strings "foo" and "1 2", namely
foo1 2
Then "foo1 foo2" can be achieved as
foo{"",(seq 1 2)}
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