you can't do that at least i dont think, you would need to use an object with the key as the dynamic so var object:Object = new Object(); object.r[gridrows] = (gridRows / 5);
----- Original Message ---- From: jmfillman <[EMAIL PROTECTED]> To: [email protected] Sent: Saturday, January 26, 2008 1:15:55 PM Subject: [flexcoders] Re: Dynamic Variable Naming Variables can't start with a number, so I need the variable to include the variable "gridRows". For example, I need that variable to be like this: var R15ColumnNumber: Number = (gridRows / 5); where the "15" in the variable name comes from the variable "gridRows" in the for loop. JF --- In [EMAIL PROTECTED] ups.com, Sherif Abdou <[EMAIL PROTECTED] ..> wrote: > > why does it say var "R" > it should be var r:String ="R" if u want it like that, what are your tring to do > > > ----- Original Message ---- > From: jmfillman <[EMAIL PROTECTED] ..> > To: [EMAIL PROTECTED] ups.com > Sent: Saturday, January 26, 2008 12:57:55 PM > Subject: [flexcoders] Dynamic Variable Naming > > I am probably overlooking something simple, but I'm trying to > dynamically name variables. See the code below, which is an example > that illustrates what I need to do. > > for (var gridRows:int= 15; gridRows < 2895;gridRows) { > var "R"+gridRows: Number = (gridRows / 5); > gridRows = (gridRows + 20); > } > > > > > > ____________ _________ _________ _________ _________ _________ _ ____________ __ > Never miss a thing. Make Yahoo your home page. > http://www.yahoo. com/r/hs > ____________________________________________________________________________________ Looking for last minute shopping deals? Find them fast with Yahoo! Search. http://tools.search.yahoo.com/newsearch/category.php?category=shopping
