use a dictionary On Jan 26, 2008 2:34 PM, Sherif Abdou <[EMAIL PROTECTED]> wrote:
> you can't do that at least i dont think, you would need to use an object > with the key as the dynamic so > * > > var > * object:Object = *new* Object(); > > object.r[gridrows] = (gridRows / 5); > > > ----- Original Message ---- > From: jmfillman <[EMAIL PROTECTED]> > To: [email protected] > Sent: Saturday, January 26, 2008 1:15:55 PM > Subject: [flexcoders] Re: Dynamic Variable Naming > > Variables can't start with a number, so I need the variable to > include the variable "gridRows". For example, I need that variable to > be like this: > > var R15ColumnNumber: Number = (gridRows / 5); > > where the "15" in the variable name comes from the > variable "gridRows" in the for loop. > > JF > > --- In [EMAIL PROTECTED] ups.com <flexcoders%40yahoogroups.com>, Sherif > Abdou <[EMAIL PROTECTED] ..> wrote: > > > > why does it say var "R" > > it should be var r:String ="R" if u want it like that, what are > your tring to do > > > > > > ----- Original Message ---- > > From: jmfillman <[EMAIL PROTECTED] ..> > > To: [EMAIL PROTECTED] ups.com <flexcoders%40yahoogroups.com> > > Sent: Saturday, January 26, 2008 12:57:55 PM > > Subject: [flexcoders] Dynamic Variable Naming > > > > I am probably overlooking something simple, but I'm trying to > > dynamically name variables. See the code below, which is an example > > that illustrates what I need to do. > > > > for (var gridRows:int= 15; gridRows < 2895;gridRows) { > > var "R"+gridRows: Number = (gridRows / 5); > > gridRows = (gridRows + 20); > > } > > > > > > > > > > > > > ____________ _________ _________ _________ _________ _________ _ > ____________ __ > > Never miss a thing. Make Yahoo your home page. > > http://www.yahoo. com/r/hs <http://www.yahoo.com/r/hs> > > > > > > ------------------------------ > Never miss a thing. Make Yahoo your > homepage.<http://us.rd.yahoo.com/evt=51438/*http://www.yahoo.com/r/hs> > -- j:pn \\no comment
