Emma,
You don't have to escape the backslash character. Simply using:
Position(Dimensions;"/";1;1)
should work.
Regards,
Lee.
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On Oct 22, 2009, at 11:28 AM, Emma Glaisher wrote:
I am manipulating fields which contain data like
8.5"/21cm
17x25x21" h/44x64x54cm h
I need to find the position of the backslash character (because
otherwise there isn’t much consistency). The calculation that seems
logical to me:
Position(Dimensions;"//";1;1)
but it returns 0. I’ve been tearing my hair out trying every
combination of // and /\ and \/ and //// and \\\\ ! Nothing works.
Surely this can be done?
Thanks
Emma
Emma Glaisher
Artworker and Database Development
Fourninety Limited
Tel: 0113 238 2447
[email protected]
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