nice discussion but what u mean by "Secondly, both SYNs should "cross
in the network". This is unlikely."
i mean its not cars on the road which will collide on network.those
two are different SYN so will it affect the network?

On Jan 18, 2008 12:39 PM, Fernando Gont <[EMAIL PROTECTED]> wrote:
> At 07:55 p.m. 17/01/2008, you wrote:
>
> >TCP specification (rfc 793) mentions about a simultaneous open and
> >it's use in distributed set ups.
> >In this case the handshake would proceed as follows:
> >
> >C -> S (Syn) .. 1
> >S -> C (Syn) .. 2
> >(1 and 2 happends almost simultaneously)
> >C -> S (Syn|Ack)
> >S -> C (Syn|Ack)
> >
> >My question is do we see this behavior in the practical world ?
>
> No, it is not.
>
> Firstly, usually only clients perform an active open of a connection
> (i.e., send a "SYN").  This has to do with the Client/Server model.
> Therefore, you won't see a SYN coming from the server.
>
> Secondly, both SYNs should "cross in the network". This is unlikely.
>
> Thirdly, in order for a simultaneous open to take place, not only
> should both systems send SYNs that cross each other in the network,
> but the client's source port should match the server's destination
> port, and the client's destination port should match the server's
> source port. This usually unlikely.
>
> Kind regards,
>
> --
> Fernando Gont
> e-mail: [EMAIL PROTECTED] || [EMAIL PROTECTED]
> PGP Fingerprint: 7809 84F5 322E 45C7 F1C9 3945 96EE A9EF D076 FFF1
>
>
>
>
>
>
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