Johan Andersson wrote:
I'm trying to transform the XML snippet below to a FO table with a width
of 3 columns. The list contain a maximum of 9 elements. Each cell should
contain an image and its description. I would appreciate any advice on
how to implement such a transformation.
XSLT questions usually get better responses on the XSL list
http://www.mulberrytech.com/xsl/xsl-list/
You problem is actualy a FAQ, the soution is called "grouping
by position" (google for details).
Hint:
<xsl:template match="list">
<fo:table ...>
< ... column decl ... >
<fo:table-body>
<xsl:apply-templates select="
list-label[position() mod 3=1]"/>
</fo:table-body>
</fo:table>
</xsl:template>
<xsl:template match="list-label">
<fo:table-row>
<xsl:for-each select=".|following-sibling::list-label
[position()<3]">
<fo:table-cell>
<fo:block>
<fo:external-graphics src="."/>
</fo:block>
<fo:block>
<xsl:apply-templates select="following-sibling::
list-text[1]"/>
</fo:block>
</fo:table-cell>
</xsl:for-each>
<fo:table-row>
...
J.Pietschmann
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