Re: Problem with transformation

[Johan Andersson]

Thank you very much for the hint and the google phrase, that solved it.
Johan Andersson
J.Pietschmann wrote:
Johan Andersson wrote:
I'm trying to transform the XML snippet below to a FO table with a 
width of 3 columns. The list contain a maximum of 9 elements. Each 
cell should contain an image and its description. I would appreciate 
any advice on how to implement such a transformation.

XSLT questions usually get better responses on the XSL list
 http://www.mulberrytech.com/xsl/xsl-list/
You problem is actualy a FAQ, the soution is called "grouping
by position" (google for details).
Hint:
  <xsl:template match="list">
    <fo:table ...>
      < ... column decl ... >
      <fo:table-body>
         <xsl:apply-templates select="
           list-label[position() mod 3=1]"/>
      </fo:table-body>
    </fo:table>
  </xsl:template>
  <xsl:template match="list-label">
    <fo:table-row>
      <xsl:for-each select=".|following-sibling::list-label
                   [position()<3]">
         <fo:table-cell>
           <fo:block>
             <fo:external-graphics src="."/>
           </fo:block>
           <fo:block>
             <xsl:apply-templates select="following-sibling::
                list-text[1]"/>
           </fo:block>
         </fo:table-cell>
      </xsl:for-each>
    <fo:table-row>
 ...
J.Pietschmann
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