Hi folks, Is there a good reason why sysctl(8) won't display _any_ output for opaque MIB entries named as arguments? I'm specifically interested in kern.proc.all. I can ``sysctl -A | grep kern.proc.all'', but it's weird that neither of these two do anything useful: sysctl -A kern.proc.all sysctl kern.proc.all Is there some sound reason for this, or am I just lost on the fringes of what sysctl(8) was designed for? Ciao, Sheldon. To Unsubscribe: send mail to [EMAIL PROTECTED] with "unsubscribe freebsd-hackers" in the body of the message
- Re: sysctl(8) and opaque MIB entries Sheldon Hearn
- Re: sysctl(8) and opaque MIB entries Dag-Erling Smorgrav
- Re: sysctl(8) and opaque MIB entries Sheldon Hearn
- Re: sysctl(8) and opaque MIB entries Dag-Erling Smorgrav
- Re: sysctl(8) and opaque MIB entries Peter Pentchev
- Re: sysctl(8) and opaque MIB ent... Dag-Erling Smorgrav
- Re: sysctl(8) and opaque MIB... Peter Pentchev
- Re: sysctl(8) and opaque... Dag-Erling Smorgrav
- Re: sysctl(8) and opaque MIB entries Poul-Henning Kamp
- Re: sysctl(8) and opaque MIB entries Peter Pentchev
- Re: sysctl(8) and opaque MIB entries Dag-Erling Smorgrav