On Tue, 05 Oct 2010 13:18:38 +0200
Eric Masson <e...@free.fr> wrote:
> Hello,
>
> I'm trying to create a script that would launch php-cgi in fastcgi
> mode. So far, I've the following script :
>
>...
>
> sig_stop="TERM"
> pidfile="/var/run/${name}/${name}.pid"
> command="/usr/sbin/daemon -f -p ${pidfile} /usr/local/bin/php-cgi"
I don't think you can do it like that. IIRC when you try to stop a
daemon it doesn't just kill the process by pid, it also sanity checks
the command in case the daemon has died and the pid was reused.
Since "daemon" wont show-up in the ps output it can't be in the command
variable.
I think you need to write a start function, something like this:
start_cmd="phpfastcgi_start"
command="/usr/local/bin/php-cgi"
phpfastcgi_start(){
echo "starting phpfastcgi."
/usr/sbin/daemon -f -p ${pidfile} ${command}
}
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