RW <rwmailli...@googlemail.com> writes: Hello,
> I don't think you can do it like that. IIRC when you try to stop a > daemon it doesn't just kill the process by pid, it also sanity checks > the command in case the daemon has died and the pid was reused. > Since "daemon" wont show-up in the ps output it can't be in the command > variable. Ok, makes sense. > I think you need to write a start function, something like this: > > > start_cmd="phpfastcgi_start" > command="/usr/local/bin/php-cgi" > > phpfastcgi_start(){ > echo "starting phpfastcgi." > /usr/sbin/daemon -f -p ${pidfile} ${command} > } Fine, it works much better now. Thanks a lot Kind Regards Éric Masson -- je n'ai jamais repondu aux AAD car je pensais qu'on pouvais pas en tant que personne qui propose un newgroup... -+- A in GNU : C'est quoi un groupe de discussion d'ailleurs ? -+- _______________________________________________ freebsd-questions@freebsd.org mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-questions To unsubscribe, send any mail to "freebsd-questions-unsubscr...@freebsd.org"