On 2 April 2011 15:20, Ryan Coleman <edi...@d3photography.com> wrote: > I found this command: > ls -R | grep ":$" | sed -e 's/:$//' -e 's/[^-][^\/]*\//--/g' -e 's/^/ /' -e > 's/-/|/' > > Which makes this: > |-Mar17 > |---1300074369-chow > |-----download > |-------small > |---1300421616-Cunningham > |-----download > |-------small > > But I want to use `du` instead to convert this > 2.0M ./Mar17/1300074369-chow/download/small > 2.0M ./Mar17/1300074369-chow/download > 2.0M ./Mar17/1300074369-chow > 2.1M ./Mar17/1300421616-Cunningham/download/small > 2.1M ./Mar17/1300421616-Cunningham/download > 2.1M ./Mar17/1300421616-Cunningham > 4.1M ./Mar17 > > into this: > |-Mar17 [4.3M] > |---1300074369-chow [2.0M] > |-----download [2.0M] > |-------small [2.0M] > |---1300421616-Cunningham [2.1M] > |-----download [2.1M] > |-------small [2.1M] > > > I realize it does it backwards and I can live with that... OR mix the two to > run the first command and run another command to get the folders total size > or something... you know? >
du -h . | awk '{a[i++]=$0} END {for (j=i-1; j>=0;) print a[j--] }' | awk '{print($2" ["$1"]");}' | sed -e 's,[^-][^/]*/,--,g' -e 's,^,|,' Does it forwards :P [crees@zeus]~/workspace/ports% du -h . | awk '{a[i++]=$0} END {for (j=i-1; j>=0;) print a[j--] }' | awk '{print($2" ["$1"]");}' | sed -e 's,[^-][^/]*/,--,g' -e 's,^,|,' |. [445K] |--net-mgmt [81K] |----CVS [5.5K] |----zabbix-server [74K] |------files [11K] |--------CVS [4.5K] |------CVS [4.5K] ... etc... |--net [31K] |----pppoa [24K] |------CVS [4.5K] |------files [12K] |--------CVS [4.5K] |----CVS [5.5K] [crees@zeus]~/workspace/ports% Any refinements requested I'll have a look at. Chris _______________________________________________ freebsd-questions@freebsd.org mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-questions To unsubscribe, send any mail to "freebsd-questions-unsubscr...@freebsd.org"