In the last episode (Jan 18), Fbsd8 said:
> In a script in am working on I need to find out the allocated
> size of a sparse file.
> The only command that comes to mind is "ls -lh"
> The "du -h" command is not appropriate because it will show
> the occupied size and not the allocated size.
> 
> I don't know how to parse out to the position in the output of that
> "ls -lh" command to pickup the file size value.
> 
> Is there some other way to do this?

For a single file, you can get the exact filesize with "stat -f %z
filename".  For the human-friendly version, "du -hA" will work.

-- 
        Dan Nelson
        dnel...@allantgroup.com
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