In a script in am working on I need to find out the allocated
size of a sparse file.
The only command that comes to mind is "ls -lh"
The "du -h" command is not appropriate because it will show
the occupied size and not the allocated size.
I don't know how to parse out to the position in the output of that
"ls -lh" command to pickup the file size value.
Is there some other way to do this?
reza wrote:
> Does this work for you
>
> $ ls -lh | awk '{print $5}'
>
> 132B
> 0B
> 3.8k
> 512B
> 3.9k
> 512B
> 512B
> 14M
> 512B
>
>
Thanks that works for me.
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