On 12/07/2013 11:19 AM, Fbsd8 wrote:
In a .sh script I'm trying to get the jid for a single jail using this code
jid=`jls -j jailname | cut -f 1- | awk '{print $1}'`
The first line output by jls is a title line which the cut command is
suppose to cut out so the first field on line 2 gets selected by the awk
command. This is not working as I want, I get the first field of the
title line.
Is the cut command the correct command to us here?
This is what the jls command shows
# /root >jls -j dir2
JID IP Address Hostname Path
15 10.0.10.24 dir2 /usr/jails/dir2
I am after the number 15
Thanks in advance
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this might do the trick for you:
jls -j jailname | tail -1 | awk '{print $1}'
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