Robin Houston <[EMAIL PROTECTED]> writes:
> On Thu, Dec 13, 2001 at 02:29:14PM +0100, Kim Schulz wrote:
> > How short kan you make a program (oneliner?) that:
> >
> > * checks if a password is 5 characters long or more
> > * checks if the password contains at least 3 alpha chars (a-zA-Z)
> > * checks if the password contains at least 2 numbers (0-9)
>
> Well, the first condition is redundant. :-)
>
> How about
> for ($password) {die if 3>y/a-zA-z//c || 2>y/0-9//c}
> ?
>
>
> It's interesting to try & do it as a single regex. The shortest
> I've found is:
>
> /(?=[a-z].*[a-z].*[a-z]).*\d.*\d/
/(?=(.*[a-z])){3}(.*\d){2}/i
(you also need the i I guess).
[...]
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