On Sat, Feb 16, 2002 at 11:10:41AM +1100, [EMAIL PROTECTED] wrote:
> Stephen Turner wrote:
> > Can someone explain to me why
> >
> > -l use POSIX;print strtol pop,36
> >
> > doesn't work? Where does the extra 0 come from?
>
> To quote myself to Dave and Jerome:
>
> BTW, because I felt you were already inundated with queries about
> it, I did not bother you with what seems to be a Perl bug that
> prevents a 32-stroke solution from working. I was too lazy to
> analyse it (instead, I trusted that Ton would, but since he has
> not posted 32, I guess it cannot be worked around).
>
> #!/usr/bin/perl -l
> use POSIX;print strtol pop,36
>
> I think this should work, but it prints a spurious trailing zero.
RTFM.
strtol String to (long) integer translation. Returns the
parsed number and the number of characters in the
unparsed portion of the string
Ronald
