I am appalled that that works. I thought perlrun was being figurative
when it described -p, but it seems not so.
[EMAIL PROTECTED]:~/work$ perl -MO=Deparse -pe ' } { $_="foo\n"' /dev/null
LINE: while (defined($_ = <ARGV>)) {
();
}
{
$_ = "foo\n";
}
continue {
print $_;
}
-e syntax OK
[EMAIL PROTECTED]:~/work$ perl -MO=Deparse -pe '$_="foo\n"' /dev/null
LINE: while (defined($_ = <ARGV>)) {
$_ = "foo\n";
}
continue {
print $_;
}
-e syntax OK
On Fri, 6 Feb 2004 [EMAIL PROTECTED] wrote:
>
>
> What does the construct "}{" mean? As in
>
>
> $ perl -pe ' } { $_="foo\n"' /dev/null
> foo
>
> I figure it has to do with how the -p switch affects the script that
> is passed to the interpreter. Is this documented anywhere?
>
> kj
>
