Leo <[EMAIL PROTECTED]> writes:
> > echo | perl -lpe 'print q'
> >
> > which outputs:
> >
> > }continue{print or die qq(-p destination: $!\n)
> >
> Well, I had no problem with the thread.... until now! How the f... does this
> work????
It gets converted to:
LINE: while (defined($_ = <ARGV>)) {
print q;}continue {die "-p destination: $!\n" unless print $_;
}
';' is a legal character to use with the quote-like operators. So
q;something; is the same as 'something'. So the manual-page shouldnt
be taken too literal either.
--
Peter Makholm | Sit back and watch the messages. This is actually
[EMAIL PROTECTED] | more important than one might think as there is a
http://hacking.dk | bug in GNU Mach whereby hitting a key during the
| boot process causes the kernel to panic
| -- GNU Hurd Installation Guide
