------- Additional Comments From pinskia at gcc dot gnu dot org 2005-07-02
17:42 -------
Since the orginal pointer is not violatile the cast will not change any thing
since the compiler can
deduce it is not violatile.
>From C99, 5.1.2.3 P3:
In the abstract machine, all expressions are evaluated as specified by the
semantics. An actual
implementation need not evaluate part of an expression if it can deduce that
its value is not used and
that no needed side effects are produced (including anycaused by calling a
function or accessing a
volatile object).
and since violatile applies the type which is being pointed to and not to the
pointer, the compiler can
deduce it is not needed.
Casting away the violatile in a pointer changes the behavior (just like const).
--
What |Removed |Added
----------------------------------------------------------------------------
Status|UNCONFIRMED |RESOLVED
Resolution| |INVALID
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=22278
