https://gcc.gnu.org/bugzilla/show_bug.cgi?id=66284
--- Comment #1 from Jonathan Wakely <redi at gcc dot gnu.org> --- (In reply to David Krauss from comment #0) > This is not conforming. Hmm, I think that's debatable. [func.wrap.func.con] says: Throws: shall not throw exceptions if f’s target is a callable object passed via reference_wrapper or a function pointer. By your interpretation, it is impossible for the target to be a callable object passed by reference_wrapper, because the target will be the reference_wrapper itself. This wording seems to imply that when the function(F) constructor is passed a reference_wrapper<T> the target should be the wrapped T. However, the function(F) constructor doesn't say anything like that, it says "*this targets a copy of f". So I'm tempted to say this is a defect in the standard. The copy constructor is trying to be helpful, and say it won't throw under certain conditions, but it does so confusingly.
