[Bug c++/96780] debuginfo for std::move and std::forward isn't useful

[redi at gcc dot gnu.org via Gcc-bugs]

https://gcc.gnu.org/bugzilla/show_bug.cgi?id=96780

--- Comment #14 from Jonathan Wakely <redi at gcc dot gnu.org> ---
(In reply to Jason Merrill from comment #10)
> It seems the libstdc++ python hooks could set that up for users with
> gdb.execute ("skip std::move")?

No, that doesn't work. You need to use 'skip "std::move<int&>"' otherwise it
doesn't skip it:

$ gdb -q -ex start -ex 'skip std::move' -ex step -ex step -ex cont -ex q a.out
Reading symbols from a.out...
Temporary breakpoint 1 at 0x40110e: file move.C, line 16.
Starting program: /tmp/a.out 

Temporary breakpoint 1, main () at move.C:16
16        int i = 0;
Function std::move will be skipped when stepping.
17        return std::move(i);
std::move<int&> (__t=@0x7fffffffd77c: 0) at move.C:11
11          { return static_cast<typename
std::remove_reference<_Tp>::type&&>(__t); }


And std::move* doesn't work either:


$ gdb -q -ex start -ex 'skip std::move*' -ex step -ex step -ex cont -ex q a.out
Reading symbols from a.out...
Temporary breakpoint 1 at 0x40110e: file move.C, line 16.
Starting program: /tmp/a.out 

Temporary breakpoint 1, main () at move.C:16
16        int i = 0;
Function std::move* will be skipped when stepping.
17        return std::move(i);
std::move<int&> (__t=@0x7fffffffd77c: 0) at move.C:11
11          { return static_cast<typename
std::remove_reference<_Tp>::type&&>(__t); }