On Fri, Jul 06, 2007 at 06:06:43AM -0600, Wachdorf, Daniel R wrote: > val = (1 << 31);
Try 1UL << 31 instead. > Should the result be 0x80000000? I understand that the bit shift is a > 32 bit operation, but shouldn't the compiler then up convert that to a > 64 bit unsigned long? No, a signed 32-bit integer is always sign extended when promoted to 64-bit. If you have C99 handy, see section 6.3.1.3 (Signed and unsigned integers). -- Daniel Jacobowitz CodeSourcery
