On Wed, 12 Dec 2007, Dave Korn wrote: > On 12 December 2007 12:14, Revital1 Eres wrote: > > > It seems that the pair m and I is missing (which indicate the memory = > > constant instruction). > > So doesn't the question then become "Why isn't reload reloading the constant > into a register"?
Yes. And the answer AFAIK is "because it doesn't see a way to move a constant into a register; it understands "r", not "p" and "q". So bviyer, add an "r" alternative. See also the "*" and "#" qualifiers. No need for bogus 0 -to- memory alternatives. brgds, H-P
