On Sun, Sep 21, 2014 at 7:49 PM, Ed Smith-Rowland <3dw...@verizon.net> wrote: > On 09/21/2014 09:56 PM, Steve Kargl wrote: >> >> + is a binary operator. 0x3ffe is a hexidecimal-constant according >> to 6.6.4.1 in n1256.pdf. 63 is, of course, a decimal-constant. >> > Also, a hex floating point uses p as an exponent for this reason... > These should just be adding integers. > > i = 0x3ffe+63; /* integral */ > > i = 0x3ffp+63; /* floating point */ > > Post the PR. > I did a lot of stuff in this area for C++11 user-defined literals. > I either caused it of I might be able to help.
6.4.8 is what matters here. pp-number is defined as: pp-number e sign pp-number E sign pp-number identifier-nondigit And /3 says: Preprocessing number tokens lexically include all floating and integer constant tokens. And /4 says: A preprocessing number does not have type or a value; it acquires both after a successful conversion (as part of translation phase 7) to a floating constant token or an integer constant token. So we have 0x3ffe+63 as one token (a pp-number) but it is not a successive token to either a floating point token or an integer constant token so it is rejected. Thanks, Andrew Pinski > > Ed >
