[gem5-users] A puzzle about how TLB is emulated

[Leon Zhao via gem5-users]

Hi all,

While I'm doing some research about how TLB is emulated in gem5 the other day, 
I noticed that TLB costs no ticks, which is quite unusual.
I tried printing current tick before and after (xxx is where I set in my print 
declaration):
(1) src/cpu/o3/lsq_impl.hh
     void LSQ<Impl>::LSQRequest::sendFragmentToTranslation(int i) {
          xxx
          the original function body
          xxx
     }
(2) src/cpu/o3/fetch_impl.hh
     DefaultFetch<Impl>::finishTranslation(const Fault &fault, const RequestPtr 
&mem_req) {
          ...
          xxx
          if (fault == NoFault) {
                ....
                fetchedCacheLines++;
                xxx
                ...
          }
          ...
      }

However, in both cases, both print functions printed the same tick number 
(starting from the very beginning). Is this normal or I found the wrong places 
to implant printf's or there's some misunderstanding about my perspective?

Here is a sample of what's left on my console:

!>> TLB starts @ tick=86592000
!>> TLB ends @ tick=86592000
!>> TLB starts @ tick=86593000
!>> TLB ends @ tick=86593000
!>> TLB starts @ tick=86597000
!>> TLB ends @ tick=86597000

Any pointers would do. Thanks in advance.
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