I still don't get the results for g 0 and g 1 :

   f=: 4 : '108-(815-1500%y)%x'
   g=: 3 : '(y-1) f y-2'

   g 0
1673
   g 1
__

Anyway, per the "harmless and possibly useful"
rational number facility,

   0j40 ": g ,.10x^1+5*i.10
 38.2777777777777777777777777777777777777778
107.9991850006850036850096850216850456850937
107.9999999918500000000685000000036850000001
107.9999999999999185000000000000068500000000
107.9999999999999999991850000000000000000007
107.9999999999999999999999918500000000000000
107.9999999999999999999999999999185000000000
107.9999999999999999999999999999999991850000
107.9999999999999999999999999999999999999919
108.0000000000000000000000000000000000000000

I'd say the limit of  g n  as n goes to infinity
is 108.



----- Original Message -----
From: John Randall <[EMAIL PROTECTED]>
Date: Friday, December 8, 2006 11:03 am
Subject: Re: [Jgeneral] exp(y). sin(y) and accuracy.

> Roger Hui wrote:
> > Is there a typo in your description?
> > g(x,y) is not defined.  Do you mean g(n+1)=f(n,n-1)?
> >
> >
> Sorry, yes.
> 
> Let f(x,y)=108-(815-1500%y)%x and let g(n+1)=f(n,n-1), with g(0)=4,
> g(1)=4.25.  Find lim g(n) as n goes to infinity.


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