R.E. Boss wrote: > You do not mean g(n+1)=f(g(n),g(n-1)) ? > Sorry to keep garbling this. I believe the following is now correct.
Let f(x,y)=108-(815-1500%y)%x and let g(n+1)=f(g(n),g(n-1)), with g(0)=4, g(1)=4.25. Then g(n)->L as n goes to infinity. The question is, what is L? Or even what is g(80)? [Hint: neither of these is 100.] ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
