Raul Miller wrote:
On Dec 25, 2007 7:06 AM, Terrence Brannon <[EMAIL PROTECTED]> wrote:
First let's go thru 1 2 3 , 0 $ 6
1. Reshaping an atomic argument to the shape of the items of the other,
So 1 2 3 is not atomic.
1 2 3 is not atomic but the items of 1 2 3 are atomic.
Yes, but my problem remains...
http://jsoftware.com/help/dictionary/d320.htm
1. Reshaping an atomic argument to the shape of the items of the other
so for 1 2 3 , 6
6 is an atomic argument and must be shaped to the shape of the ITEMS of
1 2 3
The shape of the ITEMS of 1 2 3 is ''
So 6 must be reshaped to '' which (I suppose) makes it ''
and thus you now have 1 2 3 , ''
which would be 1 2 3
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