> > I don't have a debian logon, but I do have an ia64 machine:
> Ah, in the good old days every DD had one of those :)
BTW I'm not a dd -- just have a sponsor for my packages.
Maybe someday I'll try to become a dd but for now I'm too lazy.
> The identifiers in an enumerator list are declared as constants that
> have type int and may appear wherever such are permitted.
>
> Each enumerated type shall be compatible with an integer type. The
> choice of type is implementation-defined, but shall be capable of
> representing the values of all the members of the enumeration.
thinking about this, I confused myself. Given
enum foo { FOO, BAR };
and given that the standard quoted above says FOO and BAR have type int,
why is it valid to do
enum foo x = FOO;
but not
enum foo y = FOO | BAR;
? It seems FOO and (FOO | BAR) would both have type int...
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