Hi Anatoly,
On 10/11/2017 11:58, anatoly techtonik wrote:
> It is hard to work with Git tags, because on low level hash
> of non-annotated tag is pointing to commit, but hash for
> annotated tag is pointing to tag metadata.
>
> On low level that means that there is no way to get commit
> hash from tag in a single step. If tag is annotated, you need
> to find and parse ^{} string of show-ref, if not, then look for
> string without ^{}.
That is not quite true, as you can always dereference any tag
(annotated or not) using "<tag>^0" notation, see git-rev-parse[1]:
"As a special rule, <rev>^0 means the commit itself and is used when
<rev> is the object name of a tag object that refers to a commit
object."
> So, why not just make all tags work the same so that every
> tag has its own hash and you need to dereference it in the
> same way to get commit hash?
>
> This way I could get all commit hashes with just:
>
> git show-ref --tags -d | grep "\^{}"
>
> or abandon ^{} completely and show commit hashes on -d:
>
> git show-ref --tags --dereference
>
Depending on what you would _exactly_ like to do, you could get all
tagged commit hashes like this:
git rev-list --tags --no-walk
Note that each commit will be listed only once, even if more tags
(annotated or not) point to it.
If you would like to mimic output of "git show-ref", repeating
commits for each tag pointing to it and showing full tag name as
well, you could do something like this, for example:
for tag in $(git for-each-ref --format="%(refname)" refs/tags)
do
printf '%s %s\n' "$(git rev-parse $tag^0)" "$tag"
done
Hope that helps a bit.
Regards, Buga
[1]
https://git-scm.com/docs/git-rev-parse#git-rev-parse-emltrevgtemegemHEADv1510em
