Something bugs me here.

If some type variable a is used as a parameter to another type variable t, then 
it's considered nominal. I suppose, that's because it is possible that it would 
be nominal for some specific t. But we might just know that in our application 
it's always representational, for every possible t that we would ever use. In 
this case, we might want to a) explicitly state that t's type parameter should 
always be representational, and b) at the same time make a representational. 
Seems like a probable scenario to me.

Отправлено с iPad

> 07 окт. 2013 г., в 17:26, Richard Eisenberg <e...@cis.upenn.edu> написал(а):
> 
> As you may have heard, /roles/ will be introduced with GHC 7.8. Roles are a 
> mechanism to allow for safe 0-cost conversions between newtypes and their 
> base types. GeneralizedNewtypeDeriving (GND) already did this for class 
> instances, but in an unsafe way -- the feature has essentially been 
> retrofitted to work with roles. This means that some uses of GND that appear 
> to be unsafe will no longer work. See the wiki page [1] or slides from a 
> recent presentation [2] for more info.
> 
> [1] : http://ghc.haskell.org/trac/ghc/wiki/Roles
> [2] : http://www.cis.upenn.edu/~eir/papers/2013/roles/roles-slides.pdf
> 
> I am writing because it's unclear what the *default* role should be -- that 
> is, should GND be allowed by default? Examples follow, but the critical issue 
> is this:
> 
> * If we allow GND by default anywhere it is type-safe, datatypes (even those 
> that don't export constructors) will not be abstract by default. Library 
> writers would have to use a role annotation everywhere they wish to declare a 
> datatype they do not want users to be able to inspect. (Roles still keep 
> type-*un*safe GND from happening.)
> 
> * If we disallow GND by default, then perhaps lots of current uses of GND 
> will break. Library writers will have to explicitly declare when they wish to 
> permit GND involving a datatype.
> 
> Which do we think is better?
> 
> Examples: The chief example demonstrating the problem is (a hypothetical 
> implementation of) Set:
> 
> > module Set (Set) where   -- note: no constructors exported!
> >
> > data Set a = MkSet [a]
> > insert :: Ord a => a -> Set a -> Set a
> > ...
> 
> > {-# LANGUAGE GeneralizedNewtypeDeriving, StandaloneDeriving #-}
> > module Client where
> >
> > import Set
> >
> > newtype Age = MkAge Int deriving Eq
> >
> > instance Ord Age where
> >   (MkAge a) `compare` (MkAge b) = b `compare` a   -- flip operands, 
> > reversing the order
> >
> > class HasSet a where
> >   getSet :: Set a
> >
> > instance HasSet Int where
> >   getSet = insert 2 (insert 5 empty)
> >
> > deriving instance HasSet Age
> >
> > good :: Set Int
> > good = getSet
> >
> > bad :: Set Age
> > bad = getSet
> 
> According to the way GND works, `good` and `bad` will have the same runtime 
> representation. But, using Set operations on `bad` would indeed be bad -- 
> because the Ord instance for Age is different than that for Int, Set 
> operations will fail unexpectedly on `bad`. The problem is that Set should 
> really be abstract, but we've been able to break this abstraction with GND. 
> Note that there is no type error in these operations, just wrong behavior.
> 
> So, if we default to *no* GND, then the "deriving" line above would have an 
> error and this problem wouldn't happen. If we default to *allowing* GND, then 
> the writer of Set would have to include
> > type role Set nominal
> in the definition of the Set module to prevent the use of GND. (Why that 
> peculiar annotation? See the linked further reading, above.)
> 
> Although it doesn't figure in this example, a library writer who wishes to 
> allow GND in the default-no scenario would need a similar annotation
> > type role Foo representational
> to allow it.
> 
> There are clearly reasons for and against either decision, but which is 
> better? Let the users decide!
> 
> Discussion time: 2 weeks.
> 
> Thanks!
> Richard
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