Actually, if you are looking for only lines that contain the string "univ", then you would want to grep for it:
grep univ abc.txt | cut -f3 -d, >> dev.txt. Paul's example would give you the third field of each line, even if they don't have "univ" in them. Now, if you wanted to remove the quotes, then you would need something like: grep univ abc.txt | cut -f3 -d, | sed s/\"//g >> dev.txt FYI, Kenny -------------- Original message ---------------------- From: "Whelan, Paul" <[EMAIL PROTECTED]> > Like so: cat abc.txt | cut -d, -f3 > > Thanks. > > -----Original Message----- > From: Zhao Peng [mailto:[EMAIL PROTECTED] > Sent: Tuesday, January 10, 2006 11:51 AM > To: gnhlug-discuss@mail.gnhlug.org > Subject: extract string > > Hi > > Suppose that I have a file called abc.txt, which contains the following > 5 lines (columns are delimited by ",") > > "name","age","school" > "jerry" ,"21","univ of Vermont" > "jesse","28","Dartmouth college" > "jack","18","univ of Penn" > "john","20","univ of south Florida" > > My OS is RedHat Enterprise, how could I extract the string which > contains "univ" and create an output file called def.txt, which only has > > 3 following lines: > > univ of Vermont > univ of Penn > univ of south Florida > > Please suggest the simplest command line approach. > > Thank you. > Zhao > _______________________________________________ > gnhlug-discuss mailing list > gnhlug-discuss@mail.gnhlug.org > http://mail.gnhlug.org/mailman/listinfo/gnhlug-discuss > > _______________________________________________ > gnhlug-discuss mailing list > gnhlug-discuss@mail.gnhlug.org > http://mail.gnhlug.org/mailman/listinfo/gnhlug-discuss _______________________________________________ gnhlug-discuss mailing list gnhlug-discuss@mail.gnhlug.org http://mail.gnhlug.org/mailman/listinfo/gnhlug-discuss
