> > > I just finished writing a shell script. Well, not really cause it
> > > doesn't do what I want yet. Anyway:
> > >
> > > I have a pictures directory. in that directory are three more called
> > > disk1, disk2, and disk3.
> > >
> > > What the script is *supposed* to do is "ls $1*.jpg" but when I use disk*
> > > as the variable, all I get back is the contents of disk1.
> >
> > Your description here is extremely confusing. You've got two
> > asterisks here (which probably doesn't matter much -- "disk**" doesn't
> > glob to anything different than what "disk*" would have), and you say
> > that "disk*" is a variable instead of more properly referring to it as
> > the value of a variable (the variable seems to be "$1" here).
> >
> > As a wild shot in the dark, try "ls $1*/*.jpg" .
> >
> Well, when I try "ls disk*/*.jpg > file" the file shows all three
> directories and their .jpg files. When i put the same line in the script
> it only keeps the contents of disk1 in the file. Since disk** doesn't
> glob to anything different than disk*, then putting the / in the script
> causes // to be put into the file when i only run it agains a single
> directory. Not a big problem, but putting "$1*/*.jpg" into the script
> could become a big problem when I run it against a single directory.
>
Well, it sounds like you are trying to handle tow _different_ situations,
one where you just want a list of the jpg files in one directory, and
another case where you want a list of all the jpg files in all
subdirectories in a directory. It seems you will need 2 scripts or
another argument to your script to specify which mode you want.
--Pete
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