I think what the OP wants is:
type A interface{}
type B interface{}
...
PrintInterface(A)
Meaning they want to pass the interface definition to some method.
At least that’s what I am guessing.
> On Dec 9, 2018, at 9:22 PM, Space A. <reexist...@gmail.com> wrote:
>
> reflect/* is a bit tricky. Use pointer to get interface itself.
>
> package main
>
> import (
> "fmt"
> "reflect"
> )
>
> func main() {
> test := interface{}("test")
> printInterfaceValue(test)
> }
>
> func printInterfaceValue(i interface{}) {
> switch testing := i.(type) {
> case interface{}:
> fmt.Println("is interface, with value:", testing)
> case string:
> fmt.Println("is not interface")
> }
>
> fmt.Println("reflect.Type is", reflect.TypeOf(&i).Elem())
> }
>
> Output:
> is interface, with value: test
> reflect.Type is interface {}
>
>
>
>
>
> понедельник, 10 декабря 2018 г., 5:05:12 UTC+3 пользователь Robert Engels
> написал:
>>
>> I mean reflect.Type not a type that is an interface.
>>
>>> On Dec 9, 2018, at 6:53 PM, Space A. <reexi...@gmail.com> wrote:
>>>
>>> Of course. When you "pass a value whose type implements the interface" as
>>> an interface argument to a function, you in fact pass an interface.
>>>
>>>
>>> воскресенье, 9 декабря 2018 г., 23:23:41 UTC+3 пользователь Mark Volkmann
>>> написал:
>>>>
>>>> Is it possible to pass an interface to a function in Go? I don’t want to
>>>> pass a value whose type implements the interface, I want to pass the
>>>> interface.
>>>>
>>>> --
>>>> R. Mark Volkmann
>>>> Object Computing, Inc.
>>>
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