Well, you can switch on a type, so you would think the case expression might be
able to be used elsewhere. Since the types can be created at runtime via
reflect it would seem you should be able to get a reference to the compile time
type definition as well. Seems logical to me.
> On Dec 10, 2018, at 4:34 PM, Dan Kortschak <d...@kortschak.io> wrote:
>
> Oh! Yeah, that's never going to work. How could it?
>
>> On Mon, 2018-12-10 at 13:43 -0800, Tyler Compton wrote:
>> If my interpretation of the question is correct, I think it boils
>> down to
>> whether or not it's possible to get the reflect.Type of a type in
>> order to
>> pass it to a function without first creating an instance of that
>> type. I
>> don't think it's possible but I would be interested to hear from
>> someone
>> who knows more.
>>
>> On Mon, Dec 10, 2018 at 1:28 PM Dan Kortschak <d...@kortschak.io>
>> wrote:
>>
>>>
>>> No, it is possible, but you need to pass the pointer to the
>>> interface.
>>> You can then use reflect to interrogate the interface value.
>>>
>>> The bigger question, and one that would help here would be what is
>>> it
>>> that you are actually trying to achieve.
>>>
>>>> On Mon, 2018-12-10 at 08:53 -0600, Mark Volkmann wrote:
>>>>
>>>> Yes, this is what I'm trying to do!
>>>> Perhaps this is not possible.
>>>>
>>>> On Sun, Dec 9, 2018 at 10:34 PM Robert Engels <rengels@ix.netcom.
>>>> com>
>>>> wrote:
>>>>
>>>>>
>>>>>
>>>>> I think what the OP wants is:
>>>>>
>>>>> type A interface{}
>>>>> type B interface{}
>>>>>
>>>>> ...
>>>>> PrintInterface(A)
>>>>>
>>>>> Meaning they want to pass the interface definition to some
>>>>> method.
>>>>>
>>>>> At least that’s what I am guessing.
>>>>>
>>>>> On Dec 9, 2018, at 9:22 PM, Space A. <reexist...@gmail.com>
>>>>> wrote:
>>>>>
>>>>> reflect/* is a bit tricky. Use pointer to get interface itself.
>>>>>
>>>>> package main
>>>>>
>>>>> import (
>>>>> "fmt"
>>>>> "reflect"
>>>>> )
>>>>>
>>>>> func main() {
>>>>> test := interface{}("test")
>>>>> printInterfaceValue(test)
>>>>> }
>>>>>
>>>>> func printInterfaceValue(i interface{}) {
>>>>> switch testing := i.(type) {
>>>>> case interface{}:
>>>>> fmt.Println("is interface, with value:", testing)
>>>>> case string:
>>>>> fmt.Println("is not interface")
>>>>> }
>>>>>
>>>>> fmt.Println("reflect.Type is", reflect.TypeOf(&i).Elem())
>>>>> }
>>>>>
>>>>> Output:
>>>>>
>>>>> is interface, with value: test
>>>>> reflect.Type is interface {}
>>>>>
>>>>>
>>>>>
>>>>>
>>>>>
>>>>>
>>>>> понедельник, 10 декабря 2018 г., 5:05:12 UTC+3 пользователь
>>>>> Robert
>>>>> Engels
>>>>> написал:
>>>>>>
>>>>>>
>>>>>>
>>>>>> I mean reflect.Type not a type that is an interface.
>>>>>>
>>>>>> On Dec 9, 2018, at 6:53 PM, Space A. <reexi...@gmail.com>
>>>>>> wrote:
>>>>>>
>>>>>> Of course. When you "pass a value whose type implements the
>>>>>> interface" as
>>>>>> an interface argument to a function, you in fact pass an
>>>>>> *interface*.
>>>>>>
>>>>>>
>>>>>> воскресенье, 9 декабря 2018 г., 23:23:41 UTC+3 пользователь
>>>>>> Mark
>>>>>> Volkmann
>>>>>> написал:
>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>> Is it possible to pass an interface to a function in Go? I
>>>>>>> don’t want to
>>>>>>> pass a value whose type implements the interface, I want to
>>>>>>> pass the
>>>>>>> interface.
>>>>>>>
>>>>>>> --
>>>>>>> R. Mark Volkmann
>>>>>>> Object Computing, Inc.
>>>>>>>
>>>>>> --
>>>>>> You received this message because you are subscribed to the
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>>>>>> send an
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>>>>>> For more options, visit https://groups.google.com/d/optout.
>>>>>>
>>>>>> --
>>>>> You received this message because you are subscribed to the
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>>>> --
>>>> R. Mark Volkmann
>>>> Object Computing, Inc.
>>>>
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