Sorry}, here is the right code: ( just was the effect to b working til At
5:20am sleepy and lost)
Expected behaviour is to end anonyimous func when 3s timeout is reached.
//------------------------------------------------
package main
import(
//"fmt"
"time"
"math/rand"
"log"
)
func main(){
for{
log.Println("-----------------Start")
Task()
log.Println("-----------------End")
}
}
// Trying to adapt from Concurrency in Go by Katherine Cox-Buday
func Task(){
doWork := func( done <-chan interface{}, strings <-chan string, ) <-chan
interface{} { //1
terminated := make(chan interface{})
go func() {
defer log.Println("doWork exited.")
defer close(terminated)
for {
goToSleep()
select {
//case s := <-strings:
// case s := ran():
// Do something interesting
//fmt.Println(s)
case <-done: //2
return
}
}
}()
return terminated
}
done := make(chan interface{})
terminated := doWork(done, nil)
go func() { //3
// Cancel the operation after 3 second.
time.Sleep(3 * time.Second)
log.Println("Canceling doWork goroutine reach 3s...")
close(done)
}()
<-terminated //4
log.Println("Done.")
}
done := make(chan interface{})
terminated := doWork(done, nil)
go func() { //3
// Cancel the operation after 3 second.
time.Sleep(3 * time.Second)
log.Println("Canceling doWork goroutine reach 3s...")
close(done)
}()
<-terminated //4
log.Println("Done.")
}
func goToSleep(){
rand.Seed(time.Now().UnixNano())
n := rand.Intn(12) // n will be between 0 and 10
log.Println("Sleeping ",n,"seconds..")
time.Sleep(time.Duration(n)*time.Second)
log.Println("Done sleeping!")
}
//------------------------------------------------
El lunes, 24 de febrero de 2020, 6:09:09 (UTC-3), Lutz Horn escribió:
>
> > I've tried to adapt from from "Concurrency in Go by Katherine Cox-Buday"
> to
> > understand how to apply timeout. But I don't get it.
>
> What are you trying to do? What is the expected behaviour, what happens
> instead?
>
> BTW, this code does not compile, there are same unbalanced curly brackets.
>
> Lutz
>
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