Reallly thanks for your help and guide! El martes, 25 de febrero de 2020, 5:45:17 (UTC-3), Michel Levieux escribió: > > Edit: I said "communicate with its caller" but in practice it might as > well be another goroutine or the caller of the caller, either way the > construct and the logic standing behind it are exactly the same :) > > Le mar. 25 févr. 2020 à 09:42, Michel Levieux <m.le...@capitaldata.fr > <javascript:>> a écrit : > >> Hi Juan, >> >> You cannot terminate a function execution from its caller if you did not >> pass it an argument (most likely a channel) which it can use to communicate >> with its caller, and terminate itself when the timeout is reached. >> The simplest example I can think of is the following: >> https://play.golang.org/p/KVQ7uhiWr7H, though I'm not quite sure this is >> your question, since it looks like you've already experimented with this >> construct. >> >> You can trick with signals and other constructs but channels are designed >> for that kind of need, so I suppose this is the best way to go. If you want >> something that wraps this behaviour because you need the timeout to follow >> the logic of your program, maybe package https://golang.org/pkg/context/ >> can help you. >> >> Hope this was useful! >> >> Le mar. 25 févr. 2020 à 00:45, Juan Mamani <juanmama...@gmail.com >> <javascript:>> a écrit : >> >>> Sorry again. Well, I followed your advice. Here is the link >>> https://play.golang.org/p/7DigEVsKbdx >>> How can I cancel goToSleep() when timeout is reached? >>> >>> >>> El lunes, 24 de febrero de 2020, 14:16:32 (UTC-3), Jake Montgomery >>> escribió: >>>> >>>> Your code will still not compile. In this group, it is often helpful to >>>> include a link to your code in the playground (https://play.golang.org/) >>>> using the "Share" button. That is in addition to, or instead of, posting >>>> your code in the message. This will allow others to easily run your code, >>>> but also will allow you to make sure it compiles. >>>> >>>> On Monday, February 24, 2020 at 10:01:01 AM UTC-5, Juan Mamani wrote: >>>>> >>>>> Sorry}, here is the right code: ( just was the effect to b working >>>>> til At 5:20am sleepy and lost) >>>>> >>>>> Expected behaviour is to end anonyimous func when 3s timeout is >>>>> reached. >>>>> >>>>> //------------------------------------------------ >>>>> package main >>>>> >>>>> import( >>>>> //"fmt" >>>>> "time" >>>>> "math/rand" >>>>> "log" >>>>> ) >>>>> >>>>> func main(){ >>>>> >>>>> for{ >>>>> log.Println("-----------------Start") >>>>> Task() >>>>> log.Println("-----------------End") >>>>> >>>>> } >>>>> >>>>> } >>>>> >>>>> >>>>> // Trying to adapt from Concurrency in Go by Katherine Cox-Buday >>>>> func Task(){ >>>>> >>>>> doWork := func( done <-chan interface{}, strings <-chan string, ) >>>>> <-chan interface{} { //1 >>>>> terminated := make(chan interface{}) >>>>> go func() { >>>>> defer log.Println("doWork exited.") >>>>> defer close(terminated) >>>>> for { >>>>> goToSleep() >>>>> select { >>>>> //case s := <-strings: >>>>> // case s := ran(): >>>>> // Do something interesting >>>>> //fmt.Println(s) >>>>> case <-done: //2 >>>>> return >>>>> } >>>>> } >>>>> }() >>>>> return terminated >>>>> } >>>>> >>>>> done := make(chan interface{}) >>>>> terminated := doWork(done, nil) >>>>> >>>>> go func() { //3 >>>>> // Cancel the operation after 3 second. >>>>> time.Sleep(3 * time.Second) >>>>> log.Println("Canceling doWork goroutine reach 3s...") >>>>> close(done) >>>>> }() >>>>> >>>>> <-terminated //4 >>>>> log.Println("Done.") >>>>> } >>>>> >>>>> done := make(chan interface{}) >>>>> terminated := doWork(done, nil) >>>>> >>>>> go func() { //3 >>>>> // Cancel the operation after 3 second. >>>>> time.Sleep(3 * time.Second) >>>>> log.Println("Canceling doWork goroutine reach 3s...") >>>>> close(done) >>>>> }() >>>>> >>>>> <-terminated //4 >>>>> log.Println("Done.") >>>>> } >>>>> >>>>> >>>>> >>>>> func goToSleep(){ >>>>> >>>>> >>>>> >>>>> >>>>> >>>>> >>>>> rand.Seed(time.Now().UnixNano()) >>>>> n := rand.Intn(12) // n will be between 0 and 10 >>>>> log.Println("Sleeping ",n,"seconds..") >>>>> time.Sleep(time.Duration(n)*time.Second) >>>>> log.Println("Done sleeping!") >>>>> } >>>>> >>>>> //------------------------------------------------ >>>>> >>>>> >>>>> >>>>> El lunes, 24 de febrero de 2020, 6:09:09 (UTC-3), Lutz Horn escribió: >>>>>> >>>>>> > I've tried to adapt from from "Concurrency in Go by Katherine >>>>>> Cox-Buday" to >>>>>> > understand how to apply timeout. But I don't get it. >>>>>> >>>>>> What are you trying to do? What is the expected behaviour, what >>>>>> happens instead? >>>>>> >>>>>> BTW, this code does not compile, there are same unbalanced curly >>>>>> brackets. >>>>>> >>>>>> Lutz >>>>>> >>>>> -- >>> You received this message because you are subscribed to the Google >>> Groups "golang-nuts" group. >>> To unsubscribe from this group and stop receiving emails from it, send >>> an email to golan...@googlegroups.com <javascript:>. >>> To view this discussion on the web visit >>> https://groups.google.com/d/msgid/golang-nuts/b0828575-fddf-4024-bec0-8faf5b9858a4%40googlegroups.com >>> >>> <https://groups.google.com/d/msgid/golang-nuts/b0828575-fddf-4024-bec0-8faf5b9858a4%40googlegroups.com?utm_medium=email&utm_source=footer> >>> . >>> >>
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