O(n^2)
On Thursday, 27 February 2020 18:53:01 UTC, rog wrote:
>
> If you really just want to reverse rune-by-rune, it's pretty
> straightforward:
>
> func Reverse(s string) string {
> r := make([]byte, 0, len(s))
> for len(s) > 0 {
> _, n := utf8.DecodeLastRuneInString(s)
> i := len(s) - n
> r = append(r, s[i:]...)
> s = s[:i]
> }
> return string(r)
> }
>
> That will also deal correctly with invalid utf8 encoding - all the bytes
> of the original string will be present in the result.
>
>>
>>
>>
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