This proves that the number of sums is at least the same at the number of
divisors, but it doesn't prove the equivalence. I.e. could there be other
sums...? I think you need to be more rigorous in demonstrating the
reversibility of each step.

Greg

-----Original Message-----
From: Riley [mailto:[EMAIL PROTECTED] 
Sent: Wednesday, February 11, 2004 8:16 PM
To: [EMAIL PROTECTED]
Subject: Number of odd divisors


Hello All!

After reading the kwiki on this subject provided by ton at
http://terje2.perlgolf.org/~golf-info/a1227-equivalence.html,
I think there is a more intuitive way to see that the number of ways
to write a number as the sum of sequences of consecutive positive
integers the same as the number of odd divisors of a number.

If a number, y,  is divisible by x, z times, then y can be expressed
as x + x + ... + x, z times.

We can subtract the appropriate amount from the left values, and
increment the respective right values accordingly to rewrite this as
(x - c'1) + (x - c'2) + ... + x + ... + (x + c'2) + (x + c'1)

An example demonstrates this more clearly:
35 is divisible by 7, 5 times, so we can write:

35 = 7 + 7 + 7 + 7 + 7

and rewrite this to:

35 = (7-2) + (7-1) + 7 + (7+1) + (7+2),

which is the same as:

35 = 5 + 6 + 7 + 8 + 9

For every odd divisor, there will be a corresponding summation.
The reason even divisors don't allow this should be obvious: we
need an odd number of components in order to be able to add
the same amounts on the right that we subtracted from the left...

-Riley
(o0lit3)

P.S. - Note the following example as well (to avoid confusion with
negative numbers)

27 is divisible by 3, 9 times, so we can write:

27 = 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3

and rewrite this to:

27 = (3-4) + (3-3) + (3-2) + (3-1) + 3 + (3+1) + (3+2) + (3+3) + (3+4),

which is the same as:

27 = -1 + 0 + 1 + 2 + 3 + 4 + 5 + 6 + 7

Removing all non-positive integers is easy because 0 is trivial and numbers
bellow 0 will cancel with their corresponding positive conterparts...

27 = 2 + 3 + 4 + 5 + 6 + 7




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