On Thu, 12 Feb 2004, Allen, Greg wrote:

> This proves that the number of sums is at least the same at the number of
> divisors, but it doesn't prove the equivalence. I.e. could there be other
> sums...? I think you need to be more rigorous in demonstrating the
> reversibility of each step.
>

You also need to show that every odd divisor produces a different sequence,
even after you've done the cancelling.

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Stephen Turner, Cambridge, UK    http://homepage.ntlworld.com/adelie/stephen/
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