Btw, I am not going to get all the isprocessed=true records at once. I'll get only the top 100 at any given time.
On Apr 28, 7:05 am, Pk <prakash...@gmail.com> wrote: > Thank you so much Tristan. I have another question on top of #3. > I can query on listitem parentkey = listcontainerkey and isproccess = > true. it is easier, yes. but I expect the data to be growing. there;ll > be lot of users with all their listitems stored in a single big list, > the processed and unprocessed items. Most of the times, I'll query on > the parentkey = listcontainerkey and isprocessed = true. Do you think > it's still efficient in terms of performance? > > On Apr 28, 12:51 am, Tristan <tristan.slomin...@gmail.com> wrote: > > > > > 1) yes, that should work just fine (at least in low-level datastore > > API it does) > > 2) your key should not be your security / accessibility mechanism, so > > yes, it should be fine (although using a Long id vs. keyAsString would > > be prettier). also, you want to make sure you restrict access to your > > entities by who can see the entity > > 3) since we're using approach in #1, just add that to your query, > > where listItem parentKey = listcontainerkey and isProcess=true or > > whatnot. much easier. > > > On Apr 26, 9:47 pm, Pk <prakash...@gmail.com> wrote: > > > > Hi, I have a parent ListContainer entity with key and name properties. > > > and I have a child ListItem entity with key, name and parentkey > > > properties. The parentkey simply refers to the key in ListContainer. I > > > am building a site where I list the names in listcontainer, and when > > > the user chooses a name, it'll display the top 100 list items. I have > > > three questions > > > 1) I am wondering if it would be efficient in terms of performance if > > > I use the "key on child" approach. i.e., query the listitem where > > > parentkey = listcontainerkey. > > > 2) While displaying the names of listcontainer, is it safe to pass the > > > keys to the client browser and get it back? > > > 3) The ListItem has an additional property "IsProcessed". Now, I want > > > to display only the items which are not processed. Over a period if > > > time, I am expecting lot of listitems per listcontainer. Do you think > > > it would be wise to have the processed items in separate list and > > > delete it from the original? > > > > I would very much appreciate your help as I've been struggling with > > > this requirement for long time. > > > > -- > > > You received this message because you are subscribed to the Google Groups > > > "Google App Engine for Java" group. > > > To post to this group, send email to > > > google-appengine-j...@googlegroups.com. > > > To unsubscribe from this group, send email to > > > google-appengine-java+unsubscr...@googlegroups.com. > > > For more options, visit this group > > > athttp://groups.google.com/group/google-appengine-java?hl=en. > > > -- > > You received this message because you are subscribed to the Google Groups > > "Google App Engine for Java" group. > > To post to this group, send email to google-appengine-j...@googlegroups.com. > > To unsubscribe from this group, send email to > > google-appengine-java+unsubscr...@googlegroups.com. > > For more options, visit this group > > athttp://groups.google.com/group/google-appengine-java?hl=en. > > -- > You received this message because you are subscribed to the Google Groups > "Google App Engine for Java" group. > To post to this group, send email to google-appengine-j...@googlegroups.com. > To unsubscribe from this group, send email to > google-appengine-java+unsubscr...@googlegroups.com. > For more options, visit this group > athttp://groups.google.com/group/google-appengine-java?hl=en. -- You received this message because you are subscribed to the Google Groups "Google App Engine for Java" group. To post to this group, send email to google-appengine-j...@googlegroups.com. To unsubscribe from this group, send email to google-appengine-java+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/google-appengine-java?hl=en.
