Hi Dhruva,

Thanks for your input. 
The cHeap and jHeap are considering the values which were already assigned 
to C and J, hence their start time is already sorted. Since, the intervals 
are processed according to start time. Hence, the cHeap and jHeap are 
assigning the latest task itself, since that latest task will have the 
largest end time (as start time is sorted). 
hence, I agree that cHeap and jHeap are overkill and only the latest value 
is sufficient. 

The issue with the code was that the iterator was not printing the final 
output in the right order as porker2008 pointed out.

Regards,
Manasa

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