Thanks for the response, guys. 1. I don't think the map projection I have is Mercator. Unfortunately I'm not sure what projection it is exactly, but it's apparently a commonly used one because about 50% of the maps of the USA online are identical to it. It's a more "spherical" looking projection.
2. I am not showing the Google maps or anything related to google. Given that, I think Google maps doesn't fit my needs. Do you happen to know somewhere else I could look for a solution? "Projection transformations can get VERY complex. " Indeed; a good summary of my quest so far. :) - Aaron On Oct 18, 12:34 am, mic <[email protected]> wrote: > Just note that this will only work for you if that image you are > trying to draw on top is using the same projection as google maps > does. Ie Mercator projection with WGS84 ellipsoid. > > See if you can get a google map to look the same as your image > otherwise you might be wasting your time trying to use this just to > transform lat/longs to screen coordinates. > > Projection transformations can get VERY complex. > > Regards, > Michael > > On Oct 17, 9:45 pm, Darek <[email protected]> wrote: > > > Yes, it does. > > The Map class provides a getProjection() method, which itself gives > > you the possibility to call fromLatLngToPixel(latLng:LatLng, > > zoom:Number) and fromPixelToLatLng(pixel:Point, zoom:Number, > > opt_nowrap?:Boolean). (http://code.google.com/intl/com-COM/apis/maps/ > > documentation/flash/reference.html#IProjection) > > > As far as I know you are not allowed to use the maps API without > > showing the Google map, but concult the API Terms for further > > details:http://code.google.com/intl/com-COM/apis/maps/terms.html > > > Regards, Darek -- You received this message because you are subscribed to the Google Groups "Google Maps API For Flash" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/google-maps-api-for-flash?hl=en.
